Question

Two coins are tossed simultaneously. The probability of getting at least one head is __
(Give the answer up to 2 decimal places)

Answer 1

There are four outcomes TT, TH, HT and HH, out of which the last three are favourable.
Probability of an event E, P(E) =$\frac{\text{number of favourable outcomes}}{\text{total number of outcomes}}$
Hence, the probability is $\frac{3}{4}$ = 0.75.