Two coins are tossed simultaneously. What is the probability of getting both the heads.

1

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2

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\frac{1}{2}

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\frac{1}{4}

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Solution

The correct option is C $\frac{1}{4}$
Outcome for $T_{1}$ Outcome for $T_{2}$
$H$ $H$
$H$ $T$
$T$ $T$
$T$ $H$
Let there are two tosses as $T_{1}$ and $T_{2}$ then from the above table,
Number of total outcomes $= 4$ , Number of favorable outcomes $= 4$
Hence,
The probability of getting both the heads $= \frac{1}{4} .$
This is the required solution.

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Outcome for $T_{1}$	Outcome for $T_{2}$
$H$	$H$
$H$	$T$
$T$	$T$
$T$	$H$

Two coins are tossed simultaneously. What is the probability of getting both the heads.

The correct option is C 14Outcome for T1Outcome for T2 H H H T T T T HLet there are two tosses as T1 and T2 then from the above table,Number of total outcomes =4, Number of favorable outcomes =4Hence, The probability of getting both the heads =14.This is the required solution.