Two coins are tossed simultaneously What is the probability of getting two heads?

\frac{1}{2}

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\frac{2}{3}

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\frac{1}{3}

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\frac{1}{4}

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Solution

The correct option is D $\frac{1}{4}$
When two coins are tossed the number of outcomes=4 {HH,TT,HT,TH}
The favorable outcomes=1 {HH}
$∴$ Probability of getting two head $= \frac{F a v o u r a b l e o u t c o m e s}{T o t a l n o . o f o u t c o m e s} = \frac{1}{4}$

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