Question

Two condensers of capacity $0.3\mu F$ and $0.6\mu F$ respectively are connected in series. The combination is connected across a potential of 6V. The ratio of energies stored by the condenser will be:

• A. $\frac{1}{2}$
• B. $2$
• C. $\frac{1}{4}$
• D. $4$

Answer 1

The correct option is B $2$


In series voltage is divided in inverse ratio of capacitance
$\frac{V_1}{V_2}=\frac{C_2}{C_1}=\frac{0.6}{0.3}=\frac{2}{1}{E}_1=\frac{1}{2}\times C_1{V}_1^2=\frac{1}{2}\times 0.3\mu F\times V_1^2{E}_2=\frac{1}{2}\times C_2{V}_2^2=\frac{1}{2}\times 0.6\mu F\times V_2^2\frac{E_1}{E_2}=\frac{2}{1}$