Two conductors each of resistance R ohm are connected in series and in parallel. Find the ratio of the resistance of the combination in series and in parallel.

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Solution

The correct option is B 4
In series connection, equivalent resistance, $R_{s} = R + R = 2 R$
In parallel connection, $\frac{1}{R_{p}} = \frac{1}{R} + \frac{1}{R} = \frac{2}{R}$
Equivalent resistance in parallel connection, $R_{p} = \frac{R}{2}$
Therefore, $\frac{R_{s}}{R_{p}} = \frac{2 R}{R / 2} = 4$

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Two conductors each of resistance R ohm are connected in series and in parallel. Find the ratio of the resistance of the combination in series and in parallel.

The correct option is B 4In series connection, equivalent resistance, Rs=R+R=2RIn parallel connection, 1Rp=1R+1R=2REquivalent resistance in parallel connection, Rp=R2Therefore, RsRp=2RR/2=4