Two cousins came to Rahul's place and told they also need same shirts which Rahul and the other cousins had bought earlier. Rahul took these cousins to the same shop to buy 2 same shirts. Then the total price of the clothes including previous clothes (in algebraic form) is equal to Rs. (3x + 6y) .
(Total price for the previous shopping was 3x + 4y, where x is the cost of one pant and y is the cost of one shirt)
Two cousins came to Rahul's place and told they also need same shirts which Rahul and the other cousins had bought earlier. Rahul took these cousins to the same shop to buy 2 same shirts. Then the total price of the clothes including previous clothes (in algebraic form) is equal to Rs. (3x + 6y) .
(Total price for the previous shopping was 3x + 4y, where x is the cost of one pant and y is the cost of one shirt)
The correct option is A 3x + 4y + 2x
The total price of clothes for the previous shopping was 3x + 4y, where x is the cost of one pant and y is the cost of one shirt.
Rahul is buying 2 more shirts,
Price of 2 shirts = 2y
Therefore, the total price of clothes = Rs. (3x + 4y + 2y)
Since 4y and 2y are like terms, we can add the numerical coefficients and write 4y + 2y as 6y
Total price = Rs. (3x + 6y)
3x + 4y + 2x
The total price of clothes for the previous shopping was 3x + 4y, where x is the cost of one pant and y is the cost of one shirt.
Rahul is buying 2 more shirts,
Price of 2 shirts = 2y
Therefore, the total price of clothes = Rs. (3x + 4y + 2y)
Since 4y and 2y are like terms, we can add the numerical coefficients and write 4y + 2y as 6y
Total price = Rs. (3x + 6y)
