Question

Two dice are rolled simultaneously. Find the probability that the sum of the two numbers appearing on the top is more then and equal to $10$.

Answer 1

Mximum sum possible is 6+6=12

10 cases = 4+6,6+4,5+5

11 cases = 6+5,5+6

12 cases = 6+6

Total cases = $6\times 6=36$

Favorable cases = 6

$\Rightarrow$ Probability = $\frac{6}{36}=\frac{1}{6}$