Question

Two dice are thrown simultaneously Find the probability of getting a multiple of 3 as the sum

• A. $\frac{1}{2}$
• B. $\frac{1}{3}$
• C. $\frac{1}{4}$
• D. $\frac{5}{6}$

Answer 1

The correct option is B $\frac{1}{3}$

When two dice are rolled, we have n(S) = (6 6) = 36.

getting
a multiple of 3 as the sum:

Let
E8 = event of getting a multiple of 3 as the sum. The events of a multiple of 3
as the sum will be E8 = [(1, 2), (1, 5), (2, 1), (2, 4), (3, 3), (3, 6), (4,
2), (4, 5), (5, 1), (5, 4), (6, 3) (6, 6)] = 12

Therefore,
probability of getting a multiple of 3 as the sum

$P\left(E8\right)=\frac{Numberoffavorableoutcomes}{Totalnumberofpossibleoutcome}$

$=12/36$

$=1/3$