Question

Two dice are thrown simultaneously. Find the probability of getting a sum of 12.

• A. $\frac{1}{8}$
• B. $\frac{1}{9}$
• C. $\frac{1}{12}$
• D. $\frac{1}{36}$

Answer 1

The correct option is D

$\frac{1}{36}$

Total number of outcomes when two dice are thrown =
(1,1), (1,2), (1,3), (1,4), (1,5), (1,6), (2,1), (2,2), (2,3), (2,4), (2,5), (2,6), (3,1), (3,2), (3,3), (3,4), (3,5), (3,6), (4,1), (4,2), (4,3), (4,4), (4,5), (4,6), (5,1), (5,2), (5,3), (5,4), (5,5), (5,6), (6,1), (6,2), (6,3), (6,4), (6,5), (6,6) = 36 .

Sum of 12 = (6,6)

Therefore, Probability of getting a sum of 12 = $\frac{1}{36}$.