Question

Two dice are thrown simultaneously . The probability of getting a mutiple of 2 on one die and a multiple of 3 on the other is ______

Answer 1

case 1- when dice 1 is getting a multiple of two and dice 2 is getting multiple of 3. so in this case , combination will be-

p(a)= (2,3) , (2,6), (4,3) , (4,6) , (6,3) , (6,6) = Six way

case 2- when dice 2 is getting a multiple of two and dice 1 is getting multiple of 3. so in this case , combination will be-

p(b) = (3,2) , (6,2) , (3,4) , (6,4) , (3,6), (6,6) = Six way

p(a∩b) = (6,6) = 1 way

total no of chances= p(a)+p(b)-p(a∩b) = 11

total operation = 6*6 = 36

hence probability = 11/36

Hope it helps..