Question

Two dice are thrown simultaneously. The probability of obtaining a score less than 11 is:

• A. $\frac{1}{12}$
• B. $\frac{11}{12}$
• C. $\frac{1}{9}$
• D. $\frac{5}{18}$

Answer 1

The correct option is B $\frac{11}{12}$

Total ways of throwing 2 dice =$6^2=36$
Score of 11 = {(5, 6), (6, 5)}
Score of 12 = {6, 6}
$\therefore$ Favourable ways of getting score <11 =36-3=33.
$\therefore$ Required probability =$\frac{33}{36}=\frac{11}{12}$