Two dice are thrown simultaneously, The probability of obtaining total score of seven is
636
When two dices are thrown, there are (6×6)=36 outcomes
The set of all these outcomes is the sample space given by
S = (1, 1), (1, 2), (1, 3), (1, 4), (1, 5), (1, 6),
(2, 1), (2, 2), (2, 3), (2, 4), (2, 5), (2, 6)
(3, 1), (3, 2), (3, 3), (3, 4), (3, 5), (3, 6)
(4, 1), (4, 2), (4, 3), (4, 4), (4, 5), (4, 6)
(5, 1), (5, 2), (5, 3), (5, 4), (5, 5), (5, 6)
(6, 1), (6, 2), (6, 3), (6, 4), (6, 5), (6, 6)
∴ n(S) = 36
Let E be the event of getting a total score of 7
Then E = \{(1, 6), (2, 5), (3, 4), (4, 3), (5, 2), (6, 1)\}
∴ n(E) = 6
Hence, required probability = n(E)n(S)
=636