Question

Two dice are thrown. The probability that the sum of the number appearing is more than $10$ is

• A. $\frac{1}{18}$
• B. $\frac{1}{12}$
• C. $\frac{1}{6}$
• D. None of these

Answer 1

The correct option is B

$\frac{1}{12}$

Find the required probability:

If two dice are thrown, the total number of sample space $=6^2=36.$

Favourable outcome (the sum of the number appearing is more than $10$) $=\left\{(5,6),(6,5),(6,6)\right\}$

Total number of favourable outcomes$=3$

Hence, the required probability $=\frac{\mathrm{number}\mathrm{of}\mathrm{favourable}\mathrm{outcome}}{\mathrm{total}\mathrm{number}\mathrm{of}\mathrm{outcome}}=\frac{3}{36}=\frac{1}{12}$

Hence, option (B) is correct