Question

Two dice are thrown. What is the probability that the sum of the numbers on the two dice is eight?

• A. $\frac{5}{36}$
• B. $\frac{5}{18}$
• C. $\frac{1}{4}$
• D. $\frac{1}{3}$

Answer 1

The correct option is A $\frac{5}{36}$

Favourable Cases
= {(6, 2), (2, 6), (5, 3), (3, 5), (4, 4)
= 5
Total cases=$6\times 6$= 36

So, required probability $=\frac{5}{36}$