Question

Two die are thrown. Find the probability of the event that the product of numbers on their upper faces is $12$:

• A. $\frac{1}{12}$
• B. $\frac{1}{10}$
• C. $\frac{1}{9}$
• D. $\frac{1}{6}$

Answer 1

Answer: (C)

$\frac{1}{9}$

Total number of outcomes $=36$
Favourable outcomes $(4,3),(3,4),(6,2),(2,6)=4$
Probability $=\frac{4}{36}=\frac{1}{9}$