Two different coils of self inductance L1 and L2 are placed close to each other so that the effective flux in one coil is completely linked with other. If M is the mutual inductance between them, then
A
M=L1/L2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
M=L1L2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
M=√L1L2
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
M=(L1L2)2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is CM=√L1L2
We know that, M=−e2di1/dt=−e1di2/dt Also, e1=−L1di1dt and e2=−L2di2dt ⇒M2=e1e2(di1dt)(di2dt)=L1L2 ⇒M=√L1L2