Two electric bulbs whose resistances are in the ratio 1:2 are connected in parallel to a constant voltage source the powers dissipated in them, have the ratio :-

1:2

No worries! We‘ve got your back. Try BYJU‘S free classes today!

1:1

No worries! We‘ve got your back. Try BYJU‘S free classes today!

2:1

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

1:4

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C 2:1
Power $P = V^{2} / R$
For constant voltage source, $P \propto 1 / R$
Thus, $\frac{P_{1}}{P_{2}} = \frac{R_{2}}{R_{1}} = 2 / 1$ as $(R_{1} / R_{2} = 1 / 2)$

Suggest Corrections

Similar questions

P

Q

1 : 2

Join BYJU'S Learning Program