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Acids and Bases in Water

Two electroly...

Question

Two electrolytic cells containing molten solutions of Nickel chloride and Aluminium chloride are connected in series. If same amount of electric current is passed through them, what will be the weight of Nickel obtained when $18 g m$ of Aluminium is obtained? $(A l - 27 g m / m o l e, N i - 58.5 g m / {m o l e}^{- 1})$

58.5 g m

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117 g m

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29.25 g m

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5.85 g m

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Solution

The correct option is A $58.5 g m$
$B y F a r a d a y^{'} s S e c o n d L a w$
$\frac{(m) N_{i}}{(m)_{N_{A 1}}} = \frac{(E) N_{i}}{(E)_{N_{A 1}}}$
$\frac{(m) N_{i}}{18} = \frac{58.5 \times 2}{3 \times 27}$
$(m) N_{i} = 58.5 g$

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