Question

Two electrons have been removed from each atom. Find the distance between such atoms, if they repel each other with a force of $8.8\times {10}^{-9}$ N when placed in free space.

Answer 1

$F=\frac{k{q}_1,q_2}{r^2}[here,q_{1}and{q}_2=2\times 1.6\times {10}^{-19}]$
$8.8\times {10}^{-19}=\frac{9\times {10}^9\times 3.2\times 3.2\times {10}^{-38}}{r^2}$
$r^2=\frac{9\times {10}^9\times 10.24\times {10}^{-38}}{8.8\times {10}^{-2}}r=\sqrt{\frac{9\times 16.24}{8.8}\times {10}^{-20}}$
$=\sqrt{10.47}\times {10}^{-10}$
$=3.23\times {10}^{-10}=3.23A^{\circ }$