Two elements C and D combine to form two compounds CxDy and CyDx- 0-5 mol of CyDx weigh 40 g and 1 molecule of CxDy weigh 1-66 - 10-25 kg- The atomic weight of C and D are 20 and 40 respectively- Find the value of x and y respectively-

Weight of 1 molecule of nbsp;C_xD_y = 1.66 × 10^ 25 kg So, weight of 1 mole of nbsp; C_xD_y = nbsp;1.66 × 10^ 25× N_A kg = 100 g For nbsp;C_xD_y = 20x + ...

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Standard XIII

Chemistry

Stoichiometry

Two elements ...

Question

Two elements C and D combine to form two compounds $C_{x} D_{y}$ and $C_{y} D_{x}$ . 0.5 mol of $C_{y} D_{x}$ weigh 40 g and 1 molecule of $C_{x} D_{y}$ weigh $1.66 \times 10^{- 25}$ kg. The atomic weight of C and D are 20 and 40 respectively. Find the value of x and y respectively.

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Solution

The correct option is C 1,2
weight of 1 molecule of $C_{x} D_{y}$ = $1.66 \times 10^{- 25}$ kg
So, weight of 1 mole of $C_{x} D_{y}$ = $1.66 \times 10^{- 25} \times N_{A}$ kg = 100 g
For $C_{x} D_{y}$ = 20x + 40y = 100 ....(1)
1 mol of $C_{y} D_{x}$ weigh 80 g
For $C_{y} D_{x}$ = 40x + 20y = 80 .....(2)
On solving, x = 1 and y = 2

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Two elements C and D combine to form two compounds CxDy and CyDx. 0.5 mol of CyDx weigh 40 g and 1 molecule of CxDy weigh 1.66×10−25 kg. The atomic weight of C and D are 20 and 40 respectively. Find the value of x and y respectively.

The correct option is C 1,2weight of 1 molecule of CxDy = 1.66×10−25 kg So, weight of 1 mole of CxDy = 1.66×10−25×NA kg = 100 g For CxDy = 20x + 40y = 100 ....(1) 1 mol of CyDx weigh 80 g For CyDx = 40x + 20y = 80 .....(2) On solving, x = 1 and y = 2

Two elements C and D combine to form two compounds $C_{x} D_{y}$ and $C_{y} D_{x}$ . 0.5 mol of $C_{y} D_{x}$ weigh 40 g and 1 molecule of $C_{x} D_{y}$ weigh $1.66 \times 10^{- 25}$ kg. The atomic weight of C and D are 20 and 40 respectively. Find the value of x and y respectively.