Question

Two equal chords AB and CD intersect at a point P inside the circle. If AP = 12 cm, PC = 4 cm, then find the length of chord CD.

Answer 1

Given AP = 12 cm
Since, we know that two equal chords intersect at a point inside or outside the circle, the corresponding parts of the chords are equal.

$\Rightarrow$ PD = 12 cm

Given PC = 4 cm

$\Rightarrow$ CD = PC + PD

= 4 + 12 = 16 cm