Two equal chords AB and CD intersect at a point P inside the circle- If AP -12 cm - PC -4 cm- then the length of chord CD isA- Major arcB- Minor arcC- Both halves are equal so it may be major or minor arcD- None of these

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Two equal cho...

Question

Two equal chords AB and CD intersect at a point P inside the circle. If AP = 12 cm, PC = 4 cm, then the length of chord CD is

Major arc

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Minor arc

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Both halves are equal so it may be major or minor arc

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None of these

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Solution

The correct option is B
Minor arc

Given AP = 12 cm

$\Rightarrow$ PD = 12 cm

Two equal chords intersect at a point inside or outside the circle, the corresponding parts of the chords are equal.

Given PC = 4 cm

$\Rightarrow$ CD = PC + PD

= 4 + 12 = 16 cm

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Two equal chords AB and CD intersect at a point P inside the circle. If AP = 12 cm, PC = 4 cm, then the length of chord CD is

The correct option is B Minor arc Given AP = 12 cm ⇒ PD = 12 cm Two equal chords intersect at a point inside or outside the circle, the corresponding parts of the chords are equal. Given PC = 4 cm ⇒ CD = PC + PD = 4 + 12 = 16 cm

The correct option is B
Minor arc

Given AP = 12 cm

$\Rightarrow$ PD = 12 cm

Two equal chords intersect at a point inside or outside the circle, the corresponding parts of the chords are equal.

Given PC = 4 cm

$\Rightarrow$ CD = PC + PD

= 4 + 12 = 16 cm