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Work-Energy Theorem

Two equal lum...

Question

Two equal lumps of putty are suspended side by side from two long strings so that they are just tuching. One is drawn aside so that its centre of gravity rises a vertical distance h. It is released and then collides inelastically with the other one. The vertical distance risen by the centre of gravity of the combination is

A

h

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B

3 h / 4

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C

h / 2

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D

h / 4

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Solution

The correct option is D $h / 4$
velocity before collision $= \sqrt{2 g h}$
$m (\sqrt{2 g h}) + 0 = 2 m \sqrt{2 g h^{'}}$
$2 g h = 4 (2 g h^{'})$
$h^{'} = h / 4$

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