Two equal masses are attached to the two ends of a spring of spring constant k. The masses are pulled out symmetrically to stretch the spring by a length x over its natural length. The work done by the spring on each mass is

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Solution

The correct option is D

If the spring is stretched by length x, then work done = $\frac{1}{2} k x^{2}$

So work done by each mass on the spring = $\frac{1}{4} k x^{2}$

$∴$ Work done by spring on each mass = $- \frac{1}{4} k x^{2}$

Since the the spring force and the displcement of masses are in opposite direction, work done is negative.

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Two equal masses are attached to the two ends of a spring of spring constant k. The masses are pulled out symmetrically to stretch the spring by a length x over its natural length. The work done by the spring on each mass is

The correct option is D If the spring is stretched by length x, then work done = 12kx2 So work done by each mass on the spring = 14kx2 ∴ Work done by spring on each mass = −14kx2 Since the the spring force and the displcement of masses are in opposite direction, work done is negative.