You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XIII

Physics

Maximum Height

Two equal mas...

Question

Two equal masses (m) are projected at the same angle $(θ)$ from two points separated by their range with equal velocities (v). The total momentum at the point of their collision is

$(Z e r o)$

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

$2 m v c o s θ$

No worries! We‘ve got your back. Try BYJU‘S free classes today!

$- 2 m v c o s θ$

No worries! We‘ve got your back. Try BYJU‘S free classes today!

$N o n e o f t h e s e$

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A
$(Z e r o)$

Both masses will collide at the highest point of their trajectory with equal and opposite momentum. So net momentum of the system will be zero.

Suggest Corrections

Similar questions

Two equal masses (m) are projected at the same angle $(θ)$ from two points separated by their range with equal velocities (v). The total momentum at the point of their collision is

Q. Two projectiles each of mass

m

are projected with same velocity

v

making an angle

α

and

β

from the same point in opposite directions. Find the change in their momentum at any instant :

Q. A particle of mass

m

when projected with velocity

u

at an angle

θ

to the horizontal has a range

R

. There are two walls at O and A separated by a distance

α

. Now the particle is project from O with velocity

u

and angle of projection

θ

. Where will the particle land? Choose the correct option. (All the collisions are perfectly elastic.)

Q. The horizontal ranges described by two projectiles, projected at angles

(45^{\circ} - θ)

and

(45^{\circ} + θ)

from the same point and same velocity are in the ratio.

Q. Two particles are projected with the same velocity but at angles of projection

(45^{o} - θ)

and

(45^{o} + θ)

to have maximum range. Then their horizontal ranges are in the ratio of

Join BYJU'S Learning Program

Two equal masses (m) are projected at the same angle (θ) from two points separated by their range with equal velocities (v). The total momentum at the point of their collision is

The correct option is A (Zero) Both masses will collide at the highest point of their trajectory with equal and opposite momentum. So net momentum of the system will be zero.

Two equal masses (m) are projected at the same angle $(θ)$ from two points separated by their range with equal velocities (v). The total momentum at the point of their collision is

The correct option is A
$(Z e r o)$

Both masses will collide at the highest point of their trajectory with equal and opposite momentum. So net momentum of the system will be zero.