Two equal point charges each of $3 μ C$ are separated by a certain distance in metres. If they are located at $(i + j + k)$ and $(2 i + 3 j + k)$ , then the electrostatic force between them is

16.2 \times 10^{- 3} N

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9 \times 10^{- 3} N

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10^{- 3} N

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9 \times 10^{- 2} N

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3 \times 10^{- 3} N

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Solution

The correct option is A $16.2 \times 10^{- 3} N$
The distance between two charges is $r = \sqrt{(2 - 1)^{2} + (3 - 1)^{2} + (1 - 1)^{2}} = \sqrt{5}$
By Coulomb's law, the force between two charges is $F = \frac{1}{4 π ϵ_{0}} \frac{q_{1} q_{2}}{r^{2}} = (9 \times 10^{9}) (\frac{3 \times 10^{- 6} \times 3 \times 10^{- 6}}{5}) = 16.2 \times 10^{- 3} N$

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Two equal point charges each of 3μC are separated by a certain distance in metres. If they are located at (i+j+k) and (2i+3j+k), then the electrostatic force between them is

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