Two equal poles each repel with a force of 10 newtons when placed 2 cm apart in air. The pole-strength of each in amp-meter is

10^{3}

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\frac{10^{3}}{2 π}

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2 π \times 10^{3}

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2 \times 10^{2}

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Solution

The correct option is C $2 \times 10^{2}$
$F = 10 N$
$d = 2 c m$
$m_{1} = m_{2} = m$
$F = \frac{μ m_{1} m_{2}}{4 π d^{2}}$
$10 = \frac{10^{- 7} \times m^{2}}{(2 \times 10^{- 2})^{2}}$
$m = 2 \times 10^{2} A m$

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Two equal poles each repel with a force of 10 newtons when placed 2 cm apart in air. The pole-strength of each in amp-meter is

The correct option is C 2×102F=10Nd=2cmm1=m2=mF=μm1m24πd210=10−7×m2(2×10−2)2m=2×102Am

The correct option is C $2 \times 10^{2}$
$F = 10 N$
$d = 2 c m$
$m_{1} = m_{2} = m$
$F = \frac{μ m_{1} m_{2}}{4 π d^{2}}$
$10 = \frac{10^{- 7} \times m^{2}}{(2 \times 10^{- 2})^{2}}$
$m = 2 \times 10^{2} A m$