Two flask A and B of equal volumes maintained at temperature 300K and 700K contains equal mass of He(g) and N2(g) respectively. What is the ratio of translational kinetic energy of gas in flask A to that of flask B ?
A
1:3
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B
3:1
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C
3:49
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D
None of these
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Solution
The correct option is B3:1 Moles ratio =nHenN2=w4w28=71 Ratio of translational K.E.=nHe.THenN2.TN2 =71×300700=3:1