Two functions f(x) and g(x) are defined as f(x)=log10∣∣∣x−2x2−10x+24∣∣∣ and g(x)=sin−1(2[x]−315), where [.] denotes greatest integer function, then the number of even integers for which f(x)+g(x) is defined, is
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Solution
If domain of f(x)=D1 & Domain of g(x)=D2 ⇒ Domain of f(x)+g(x)=D1∩D2 For D1
x−2x2−10x+24≠0⇒x≠2,4,6 And for D2
−1≤2[x]−315≤1⇒−6≤[x]≤9 ⇒x∈[−6,10) So the possible even integers are even integers in D1∩D2={−6,−4,−2,0,8} Only 5 integers, hence answer is 5.