You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard IX

Chemistry

Liquefaction

Two gases A...

Question

Two gases $A$ and $B$ are exerting pressure $p_{1}$ and $p_{2}$ in two different container having equal volume. If equal amount of charcoal is added to both container and pressure reduced to $\frac{p_{1}}{2}$ and $\frac{p_{2}}{4}$ respect. Which statement is true ?

B

is easily liquefiable than

A

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Critical temperature of

B

is more than

A

No worries! We‘ve got your back. Try BYJU‘S free classes today!

B

adsorbs easily than

A

on Charcoal

No worries! We‘ve got your back. Try BYJU‘S free classes today!

All of the above

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is D All of the above
$\begin{matrix} Pressure of B has decreased more than A. so, we can say that B is more absorbed by charcoal than A . so B is easily liquefiable than A . critical temperature of B is more than A . So D) All of the above is correct. \end{matrix}$

Suggest Corrections

Similar questions

Q. Two containers

A and B

contain ideal gases, helium and oxygen respectively. Volume of both containers are equal, and pressure is also equal. Container

A

has twice the number of molecules than container

B .

V_{A} and V_{B}

represent the rms speed of gases in containers

A and B

respectively, then

Q. Two containers of equal volume contain the same gas at different pressures

P_{1}

and

P_{2}

and absolute temperatures

T_{1}

and

T_{2}

, respectively. On joining the vessels, the gas reaches a common pressure

P

and common temperature

T

. The ratio

\frac{P}{T}

is equal to

Q. Two containers of equal volume contain the same gas at different pressures

P_{1}

and

P_{2}

and absolute temperatures

T_{1}

and

T_{2}

, respectively. On joining the vessels, the gas reaches a common pressure

P

and common temperature

T

. The ratio

\frac{P}{T}

is equal to

Two containers of equal volume contain the same gas at pressures $P_{1}$ and $P_{2}$ and absolute temperatures $T_{1}$ and $T_{2}$ respectively. On joining the vessels, the gas reaches a common pressure P and common temperature T. The ratio $\frac{P}{T}$ is equal to

Q. Two non-conducting containers having volume

V_{1}

and

V_{2}

contain mono-atomic and diatomic gases respectively. They are connected as shown in the figure. Pressure and temperature in the two containers are

P_{1}, T_{1}

and

P_{2}, T_{2}

respectively. Initially, the stopcock is closed, if the stopcock is opened, find the final pressure and temperature

Join BYJU'S Learning Program

Two gases A and B are exerting pressure p1 and p2 in two different container having equal volume. If equal amount of charcoal is added to both container and pressure reduced to p12 and p24 respect. Which statement is true ?

The correct option is D All of the above Pressure of B has decreased more than A. so, we can say that B is more absorbed by charcoal than A . so B is easily liquefiable than A . critical temperature of B is more than A . So D) All of the above is correct.

Two gases $A$ and $B$ are exerting pressure $p_{1}$ and $p_{2}$ in two different container having equal volume. If equal amount of charcoal is added to both container and pressure reduced to $\frac{p_{1}}{2}$ and $\frac{p_{2}}{4}$ respect. Which statement is true ?

The correct option is D All of the above
$\begin{matrix} Pressure of B has decreased more than A. so, we can say that B is more absorbed by charcoal than A . so B is easily liquefiable than A . critical temperature of B is more than A . So D) All of the above is correct. \end{matrix}$