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Two containers A and B contain ideal gases, helium and oxygen respectively. Volume of both containers are equal, and pressure is also equal. Container A has twice the number of molecules than container B. If VA and VB represent the rms speed of gases in containers A and B respectively, then

A
VAVB=2
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B
VAVB=4
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C
VAVB=2
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D
VAVB=8
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Solution

The correct option is C VAVB=2
As we know that the ideal gas is given by : PV=nRT

For A:PV=2nRTA(1)
For B:PV=nRTB(2)

Given that pressure and volume are same therefore,
from equations (1) and (2)khj
TB=2TA

RMS speed of gas is given by :

Vrms=3RTM

VAVB=3RTA43RTB32

VAVB=3RTA43RTA32=2

VAVB=2




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