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Question

Two gases occupy two containers A and B. The gas in A, of volume 0.10 m3, exerts a pressure of 1.40 MPa and that in B, of volume 0.15 m3, exerts a pressure of 0.7 MPa. The two containers are joined by a tube of negligible volume and the gases are allowed to intermingle. Then, if the temperature remains constant, the final pressure in the containers will be ( in MPa):

A
0.70
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B
0.98
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C
1.40
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D
2.10
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Solution

The correct option is B 0.98
Given,
Volume of gas in container A (VA)=0.10 m3
Volume of gas in container B (VB)=0.15 m3
Pressure exerted by gas in container A (PA)=1.40 MPa
Pressure exerted by gas in container B (PB)=0.7 MPa
Let P and V be the pressure and volume of the gas after the two containers are joined together.
As the quantity of gas remains constant, n=nA+nB
Since the temperature is kept constant, by using ideal gas equation, we can write that,
P(VA+VB)RT=PAVART+PBVBRT (V=VA+VB)
P=PAVA+PBVBVA+VB=1.40×0.1+0.7×0.150.1+0.15
P=0.98 MPa
Thus, option (b) is the correct answer.

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