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Real Gases

Two Gases X a...

Question

Two Gases X and Y have densities $d_{x} = 3 d_{y}$ and Molecular Masses , $M_{x} = 0.5 M_{y}$ . Then, the ratio of their pressures, i.e. $P_{x} : P_{y}$ would be

A

1/4

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B

1/6

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C

4

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D

6

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Solution

The correct option is D
6

$\frac{P_{1}}{P_{2}} = \frac{d_{1} R T M_{2}}{M_{1} d_{2} R T} = \frac{d_{1} M_{2}}{M_{1} d_{2}}$

$∴ \frac{P_{x}}{P_{y}} = \frac{d_{x} M_{y}}{d_{y} M_{x}} = \frac{3 \times 1}{0.5} = 6$

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