Two geometric mean between the number $1$ and $64$ are

1

and

64

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4

and

16

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2

and

16

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2

and

8

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Solution

The correct option is B $4$ and $16$
$L e t m e a n s a r e a a n d b t h e n 1, a, b, 64 a r e i n G P ∴ 64 = 1 \times r^{2} ∴ r = 4 t h e n a = 1 \times r = 4 b = 1 \times r^{2} = 16$ .
So, the correct option is '4 and 16'.

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^{'} \div^{'}

^{'} \div^{'}

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