Question

Two glass bulbs A and B at same temperature are connected by a very small tube having a stop cork. Bulb A has a volume of $100c{m}^3$ and contained the gas while bulb B was empty. On opening the stop cork, the pressure fell down to 20%. What is the volume of the bulb B?

Answer 1

Given, initial volume=$100c{m}^3$ = $V_A$

initial Pressure = P = $P_1$

final pressure = $\frac{20}{100}$P = 0.2P = $P_2$

$\Rightarrow$Boyle's law, $P_1{V}_A=P_2{V}_2\left(P\right)\left(100c{m}^3\right)=\left(0.2P\right)V_2{V}_2=500c{m}^3\Rightarrow \text{total volume =}{V}_A+V_B$

So, the volume of the bulb B = 500 - 100 = 400 $c{m}^3$