Question

Two glucose solutions are mixed. One has a volume of 480 mL and a concentration of 1.50 M and the second has a volume of 520 mL and concentration 1.20 M. The molarity of final solution is :

• A. 1.20 M
• B. 1.50 M
• C. 1.344 M
• D. 2.70 M

Answer 1

Answer: (C)

1.344 M

$M_1{V}_1+M_2{V}_2=M_3{V}_3$
$(V_3=V_1+V_2)$
$1.5\times 480+1.2\times 520=M_3\times 1000$
$M_3=1.344M$