Question

Two solutions of a substance (non-electrolyte) are mixed in the following manner.

480 ml of 1.5 M first solution + 520 ml of 1.2 M second solution.

What is the molarity of the final mixture?

• A. $1.20M$
• B. $1.50M$
• C. $1.344M$
• D. $2.70M$

Answer 1

The correct option is C $1.344M$

$M_{net}=\frac{M_1{V}_1+M_2{V}_2}{V_1+V_2}$

$=\frac{1.5\times 480+1.2\times 520}{480+520}$

$=\frac{1344}{1000}$

$=1.344M$