CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Two separate solutions of a non-electrolyte substance are mixed. 480 mL of a 1.5 M solution is mixed with 520 mL of a 1.2 M solution. What is the molarity of the final mixture?

A
3.76 M
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
5.52 M
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
7.13 M
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
1.34 M
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution

The correct option is D 1.34 M
Conserving the total moles before and after mixing:
M1V1+M2V2=MV
where M2 and V2 are the molarity and volume of 1.2 M solution.
M1 and V1 are the molarity and volume of 1.5 M solution and M and V are the molarity and volume of the mixture
(1.5×480)+(1.2×520)=M×1000
On solving, M=1.34 M

flag
Suggest Corrections
thumbs-up
4
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Reactions in Solutions
CHEMISTRY
Watch in App
Join BYJU'S Learning Program
CrossIcon