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Question

Two groups are competing for the position on the Board of directors of a corporation. The probabilities that the first and the second groups will win are 0.6 and 0.4 respectively. Further, if the first group wins, the probability of introducing a new product is 0.7 and the corresponding probability is 0.3 if the second group wins. Find the probability that the new product introduced was by the second group.

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Solution

Let E1 and E2 be the respective events that the first group and the second group win the competition. Let A be the event of introducing a new product.

P(E1)= Probability that the first group wins the competition =0.6
P(E2)= Probability that the second group wins the competition =0.4
P(A|E1)= Probability of introducing a new product if the first group wins =0.7
P(A|E2)= Probability of introducing a new product if the second group wins =0.3
The probability that the new product is introduced by the second group is given by P(E2|A).
By using Baye's theorem, we obtain

P(E2|A)=P(E2)P(A|E2)P(E1)P(A|E1)+P(E2)P(A|E2)

=0.4×0.30.6×0.7+0.4×0.3

=0.120.42+0.12

=0.120.54

=1254

=29=0.22

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