Two identical batteries each of e.m.f.2V and internal resistance 1Ω are available to produce heat in an external resistance by passing a current through it. The maximum power that can be developed across R using these batteries is
A
3.2W
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B
2.0W
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C
1.28W
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D
8/9W
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Solution
The correct option is B2.0W For maximum current, the two batteries should be connected in series. The current will be maximum when external resistance is equal to the total internal resistance of cells i.e R=r+r=1+1=2Ω Thus, E+E=I(R+r+r)⇒I=2ER+2r=2×22+2=1A Maximum power, P=I2R=12×2=2W