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Question

Two identical blocks A and B, each of mass m=2 kg are connected to the ends of an ideal spring having force constant k=1000 Nm1. System of these blocks and spring is placed on a rough floor. Coefficient of friction between blocks and floor is μ=0.5. Block B is pressed towards left so that spring gets compressed.
Initial minimum compression x0 of spring such that block A leaves contact with the wall when system is released is:
4279_99f56782ac094bae8d57a2457f22b087.png

A
3 cm
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B
4 cm
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C
5 cm
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D
6 cm
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Solution

The correct option is A 3 cm
Block A will move when the extension on the spring xf=μmg/k

Initial state: xi compression. Total displacement of block B : xi+xf

Initial Energy : 12kx2i

Final Energy : 12kx2f

Work Done : (By friction) : μmg(xi+xf)

Change in energy = Work done by external forces.

μmg(xi+xf)=12k(x2ix2f)

2μmg/k+xf=xi

xi=3μmg/k=0.03 m=3 cm

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