Two identical objects each of radii R and masses m1 and m2 are suspended using two strings of equal length L as shown in the figure (R<<L). The angle θ which mass m2 makes with the vertical is approximately.
A
m1R(m1+m2)L
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B
2m1R(m1+m2)L
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C
2m2R(m1+m2)L
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D
m2R(m1+m2)L
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Solution
The correct option is C2m1R(m1+m2)L Distance of center of mass from m2' d=m1(m1+m2)×2R θ=distance(d)L θ=m1(m1+m2)×2RL.