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Question

Two identical objects each of radii R and masses m1 and m2 are suspended using two strings of equal length L as shown in the figure (R<<L). The angle θ which mass m2 makes with the vertical is approximately.

631331_d58f451f4ac1482fa51dff9cd5bd7334.jpg

A
m1R(m1+m2)L
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B
2m1R(m1+m2)L
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C
2m2R(m1+m2)L
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D
m2R(m1+m2)L
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Solution

The correct option is C 2m1R(m1+m2)L
Distance of center of mass from m2'
d=m1(m1+m2)×2R
θ=distance(d)L
θ=m1(m1+m2)×2RL.
676293_631331_ans_c03861a4aa814ee48d90560bcb1a4cad.jpg

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