Question

Two identical parallel plate capacitors are connected in series and then joined with a battery of $100V$. A sheet of dielectric constant $4.0$ is inserted between the plates of second capacitor. The potential difference across the capacitors will be respectively.

• A. $50V,50V$
• B. $80V,20V$
• C. $20V,80V$
• D. $75V,25V$

Answer 1

The correct option is C $20V,80V$

Two identical parallel plates capacitors are connected in series voltage $=100V$

dielectric constant $=4$

$V_1=\frac{e_{2}V}{C_1+C_2}=\frac{4d\times 100}{50}=80V$

$V_2=\frac{{ϵ}_{0}V}{C_1+C_2}=20V$