Two identical resistors each of resistance 2 ohms are connected in (I) series (II) in parallel to a battery of 12V. Calculate the ratio of power consumed

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Solution

Dear student,

(1) IN SERIES

Total Resistance in Series = R₁ + R₂
= 2 + 2
= 4 Ohm
Potential Difference(V) = 12V
Current(I)= V/R
=12/4
=3Ampere
Power = VI
= 123
=36 Watts

(2) IN PARALLEL
1/R₁ + 1/R₂ = 1/Rₐ (Where Rₐ is the total resistance)
1/2 + 1/2 = 1/Rₐ
2/2 =1/Rₐ
1/1 = 1/Rₐ
1 Ohm = Rₐ

Voltage (V)= 12Volts
Current(I)= V/R
= 12 Ampere
Power= VI
= 1212
= 144 Watt

Power in series : Power in Parallel
36 : 144
1 : 4

Regards

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