Two lamp posts are of equal height. A boy standing mid-way between then observes the elevation of the top of either post to be 30∘. After walking 15 m towards one of them, he observes the elevation of it stop to be 60∘. Find the heights of the posts and the distance between them.
45 m
From right angled triangle ΔABC, we have
tan60∘=yx
⇒√3=yx
⇒y=√3x.....(i)
Similar way, from right angled triangle ΔABD
tan30∘=yx+15
1√3=yx+15
x+15=√3y
⇒x+15=√3(√3x)
⇒x+15=3x
⇒3x−x=15
⇒2x=15
∴x=7.5 m
Hence, y=√3×7.5
∴y=12.975 m
BD=x+15=7.5+15=22.5 m
Since, D is mid point of BE.
So, BE=2BD
=2(22.5)
∴BE=45 m
Hence, the distance between the poles =45 m