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Hydroboration Oxidation

Two liquids A...

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Two liquids A and B mixed in 1:4 mole ratio to form an ideal solution.If pure liquid A and B exerts a pressure of 75mmHg and 22mmHg respectively, the vapour pressure of liquid A in the vapour phase would be

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Q. Two liquids A and B are mixed in 1 : 4 mole ratio to from an ideal solution. If they exert vapour pressures of 75 mmHg and 22 mmHg respectively, the mole fraction of liquid of A in the vapour phase would be

Q. If vapour pressure of pure liquid

A

100 mm Hg

and Vapour pressure of pure liquid

B

150 mm Hg

2

A

3

B

are mixed to form an ideal solution. The vapour pressure of solution will be:

Q. The vapour pressure of a pure liquid A is

80

300 K

. It forms an ideal solution with liquid B. When the mole fraction of B is

0.4

, the total pressure was to be

88

mmHg. The vapour pressure of liquid B would be?

X

Y

from an ideal solution. At

300 K

, a vapour pressure of the solution containing

1

X

3

Y

550

m m H g

. At the same temperature, if

1

Y

is further added to this solution, a vapour pressure of the solution increased by

10

m m H g

. Vapour pressure ( in mmHg) of

X

Y

in their pure states will be respectively:

80^{o}

C, the vapour pressure of pure liquid

A

is 520 mmHg and that of pure liquid

B

is 1000 mmHg. If a mixture solution of

A

B

80^{o}

and 1 atm pressure, the amount of

A

(mole percent) in the mixture is:

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Hydroboration Oxidation

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