Two liquids A and B have P∘A:P∘B=1:3 at a certain temperature. If the mole fraction ratio of xA:xB=1:3, the mole fraction of A in vapour in equilibrium with the solution at a given temperature is
A
0.1
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B
0.2
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C
0.5
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D
1
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Solution
The correct option is A 0.1 From Raoult's law, Vapour pressure of A is PA=xAP0A
and Vapour pressure of B is PB=xBP0B
Now mole fraction of A in vapour is yA=PAPA+PB=xAP0AxAP0A+xBP0B yA=11+9=0.1