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Question

# Two long straight wires, each carrying an electric current of 5 A, are kept parallel to each other at a separation of 2.5 cm. Find the magnitude of the magnetic force experienced by 10 cm of a wire.

A
4.0×104N
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B
3.5×106N
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C
2.0×105N
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D
2.0×109N
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Solution

## The correct option is B 2.0×10−5NGiven: i1=i2=5A;d=2.5cm=0.025m;l=10cm=0.10mThe magnetic force per unit length between two long straight parallel current carrying wires, placed in vacuum, separated by a distance d, is given by: F/l=μ0.i1i22πd F=μ0.i1i2l2πdHence, F=4π×10−7×5×5×0.102π×0.025=2.0×10−5N

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