CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon


Question

Two long thin charged rods with charge density λ each are placed parallel to each other at a distance d apart. The force per unit length exerted on one rod by the other will be (where k=14πϵ0)
 
  1. k2λd
  2. k2λ2d
  3. k2λd2
  4. k2λ2d2


Solution

The correct option is B k2λ2d
Electric field due to wire (2) =14πϵ02λ2R
Charge per unit length on wire (1) =λ2
Force per unit length on wire (1) =λ1×E
=λ×14πϵ02λ2R
=K(2λ1λ2)R
Here λ1=λ2=λ and R = d
F=K.2λ2d
Option (2) is correct.

flag
 Suggest corrections
thumbs-up
 
0 Upvotes


Similar questions
QuestionImage
QuestionImage
View More...


People also searched for
QuestionImage
QuestionImage
View More...



footer-image