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Question

Two masses 2m and m are connected by an inextensible light string. The string is passing over a light frictionless pulley. The mass 2m is resting on a surface and mass m is hanging in air as shown in Fig. A particle of mass m strikes the mass m from below in case (I) with a velocity v0 and in case (II) strikes mass m with a velocity v0 from top and sticks to it in both cases. Then,

A
The conservation of linear momentum can be applied in both the cases just before and just after collision
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B
The conservation of linear momentum can be applied in case I but cannot be applied in case II just before and just after collision
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C
The ratio of velocities of mass m just after collision in first and second cases is 12
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D
The ratio of velocities of mass m just after collision in first and second case is 2.
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Solution

The correct option is D The ratio of velocities of mass m just after collision in first and second case is 2.
In the first case: (m+m)v1=mv0v1=v02
In the second case:
T dt=(m+m)vmv0 (i)
T dt=2mv (ii)
From Eqs. (i) and (ii),
4mv=mv0v=v04 and required ratio = 2

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